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Mission March 2026-27 Corbon compounds Level 1 & Level 2 Answers

Mission March 2026-27 Corbon And it's Compounds Level 1 & Level 2 Answers



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1. Fill the table with suitable answers related to functional groups, structural formulae, ex-amples and suffixes.

Structural Formula Functional Group Name Suffix Example
R-OH Alcohol -ol C2H5OH
R-CHO Aldehyde -al CH3CHO
R-COOH Carboxylic acid -oic acid CH3COOH
R-CO-R Ketone -one CH3COCH3

2. Complete the table of alkanes, alkenes and alkynes based on the number of carbon atoms.

No. of CorbonsAlkanesAlkenesAlkynes
2EthaneEthene
Ethyne
3PropanePripenePropyne
4ButaneButeneButyne
5PentanePentenePentyne

3. Explain the following

a) Addition reaction of unsaturated hydrocarbons

An addition reaction is a reaction in which atoms or groups of atoms are added to an unsaturated hydrocarbon at the double or triple bond to form a saturated compound.

Example:

CH₂=CH₂ + H₂ → CH₃–CH₃

Ethene + Hydrogen → Ethane

This reaction takes place in the presence of a catalyst such as Ni/Pt/Pd.

b) Substitution reaction of saturated hydrocarbons

A substitution reaction is a reaction in which one or more hydrogen atoms of a saturated hydrocarbon are replaced by another atom or group of atoms.

Example:

CH₄ + Cl₂ → CH₃Cl + HCl

Methane + Chlorine → Chloromethane + Hydrogen chloride

The reaction occurs in the presence of sunlight (UV light).

4. Explain the cleansing action of soap with a well-labelled diagram

A soap molecule has two parts:

Hydrophilic end – water-loving ionic end.

Hydrophobic end – water-repelling hydrocarbon chain that attracts oil and grease.

When soap is added to water containing oily dirt, the hydrophobic ends attach themselves to the grease, while the hydrophilic ends remain in water. Many soap molecules surround the grease particle and form a micelle.

On rubbing and washing with water, the grease-containing micelles are removed.

Diagram:


                 Water

       ○  ○  ○  ○  ○  ○

        \ |  \ |  \ | /

         \|   \|   \|/

       ┌─────────────────┐

       │   OIL / GREASE  │

       └─────────────────┘

         /|   /|   /|\

        / |  / |  / | \

       ○  ○  ○  ○  ○  ○


○ = Hydrophilic end (water-loving)

Lines = Hydrophobic hydrocarbon chains

                 ↓

        MICELLE FORMATION

                 ↓

       Dirt/grease is washed away

5. Distinguish between soap and detergent

Soap

SoapDetergent
Soaps are sodium or potassium salts of long Chain Fatty AcidsDetergent s are salts of long chain alkyle benzene sulfonates or alkyl sulfonates
They are Generally less effective in hard waterThey are  effective in hard water
They form scumwith Ca2+ and Mg2+ ionsThey Generally don't form insoluble scum with Ca2+ and Mg2+ ions
Example: Sodium StearateExample Sodium alkyle benzene sulphonate


2 Marks Questions

1. What are the two properties of carbon that lead to the large number of carbon compounds?

The two important properties are:

Catenation: Carbon atoms can bond with one another to form long chains, branched chains and rings.

Tetravalency: Carbon has a valency of four and can form four covalent bonds with carbon and other elements.

2. Explain catenation with an example.

Catenation is the property of carbon by which carbon atoms form bonds with other carbon atoms to produce long chains, branched chains and rings.

Example:

CH₃–CH₂–CH₂–CH₂–CH₃

This is a chain of five carbon atoms (pentane).

3. What is allotropy? Write the allotropes of carbon.

Allotropy is the property of an element to exist in two or more different forms in the same physical state.

Important allotropes of carbon are:

Diamond

Graphite

Fullerenes (such as C₆₀)

4. Name the following functional groups

(i) –CHO → Aldehyde group

(ii) >C=O → Ketone (carbonyl) group

5. What are hydrocarbons? How are they classified?

Hydrocarbons are compounds containing only carbon and hydrogen.

They are mainly classified as:

Saturated hydrocarbons – contain only single C–C bonds.

Example: Ethane (C₂H₆)

Unsaturated hydrocarbons – contain double or triple bonds.

Alkenes – contain C=C double bond. Example: Ethene (C₂H₄)

Alkynes – contain C≡C triple bond. Example: Ethyne (C₂H₂)


6. Give two examples each of saturated and unsaturated hydrocarbons.

Saturated hydrocarbons:

Methane – CH₄

Ethane – C₂H₆

Unsaturated hydrocarbons:

Ethene – C₂H₄

Ethyne – C₂H₂

7. Give one example each of a carbon compound containing:

1. Alcohol functional group:

Ethanol – C₂H₅OH

2. Carboxylic acid functional group:

Ethanoic acid – CH₃COOH

8. Why are cooking oils hydrogenated before making vanaspati ghee?

Cooking oils contain unsaturated fatty acids. Hydrogenation adds hydrogen to the double bonds in these oils in the presence of a nickel catalyst, converting them into more saturated and solid fats.

Example:

Unsaturated oil + H₂ → Saturated fat

(Ni catalyst)

Thus, hydrogenation helps convert liquid vegetable oils into solid/semi-solid vanaspati ghee.

9. A student says ethanol and ethanoic acid have the same properties. Is the statement correct?

No, the statement is incorrect.

Ethanol and ethanoic acid have different functional groups and therefore different physical and chemical properties.

Ethanol: C₂H₅OH — alcohol

Ethanoic acid: CH₃COOH — carboxylic acid

Ethanoic acid turns blue litmus red, whereas ethanol does not.

10. Suggest a way to identify whether a carbon compound is saturated or unsaturated.

Treat the compound with bromine water.

Unsaturated compound: Decolourises bromine water.

Saturated compound: Does not decolourise bromine water under ordinary conditions.

Another test is the alkaline KMnO₄ test.


1 Mark Questions

1. A student proposes to make a sweet-smelling compound from ethanol and acetic acid. Which reaction should be carried out?

Answer: Esterification reaction.

Ethanol reacts with ethanoic acid in the presence of concentrated H₂SO₄ to form ethyl ethanoate, which has a sweet/fruity smell.

C₂H₅OH + CH₃COOH → CH₃COOC₂H₅ + H₂O

2. Write the structural formula of any hydrocarbon with eight carbon atoms.

Octane:

CH₃–CH₂–CH₂–CH₂–CH₂–CH₂–CH₂–CH₃

3. Identify the functional group present in propanal.

Answer: Aldehyde group (–CHO)

4. Which of the following undergoes substitution reaction?

A) CH₄

B) C₃H₆

C) C₂H₂

D) C₇H₁₄

Answer: A) CH₄ (Methane)

5. Which of the following hydrocarbons undergoes addition reaction?

A) C₂H₆

B) C₃H₈

C) C₃H₆

D) CH₄

Answer: C) C₃H₆ (Propene)


6. Identify the alkene among the following hydrocarbons.

A) C₂H₆

B) C₃H₈

C) C₃H₆

D) CH₄

Answer: C) C₃H₆ (Propene)

7. The general formula of alkanes is CₙH₂ₙ₊₂. Write the first member of alkanes.

Answer: Methane (CH₄)

8. A hydrocarbon has four carbon atoms and ten hydrogen atoms. Write its name

Formula = C₄H₁₀

Answer: Butane

9. Which compound is formed when two carbon atoms are linked by a single bond and six hydrogen atoms are added?

Answer: Ethane (C₂H₆)

Structural formula:

CH₃–CH₃

10. How can you convert ethene into ethane?

By hydrogenation of ethene in the presence of a nickel catalyst.

CH₂=CH₂ + H₂ → CH₃–CH₃

(Ni catalyst)


11. Give any example of an unsaturated hydrocarbon.

Answer: Ethene (C₂H₄)

12. How many hydrogen atoms are present in Butane?

Butane = C₄H₁₀

Answer: 10 hydrogen atoms

13. Which type of bond is present between carbon atoms in ethene?

Answer: Double covalent bond (C=C).


LEVEL – 2: SHINING STAR

8 Marks Questions

1. How can ethanol and ethanoic acid be differentiated based on their physical and chemical properties?

Property Ethanol Ethanoic acid
Formula C₂H₅OH CH₃COOH
Functional group –OH (Alcohol) –COOH (Carboxylic acid)
Smell Characteristic alcoholic smell Vinegar-like smell
Litmus test Does not change blue litmus Turns blue litmus red
Reaction with NaHCO₃ No brisk reaction Produces CO₂ gas with effervescence
Nature Neutral Acidic
Boiling point About 78°C About 118°C
Common use Solvent, fuel, sanitiser Vinegar, food preservative

Important test:


CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂↑


The evolution of CO₂ gas confirms ethanoic acid.


2. Explain the nature of the covalent bond using bond formation in CH₃Cl.

A covalent bond is formed by the sharing of electrons between atoms.

In CH₃Cl (chloromethane):

Carbon has 4 valence electrons and needs four more electrons to complete its octet.

Each hydrogen shares one electron with carbon, forming three C–H covalent bonds.

Chlorine has 7 valence electrons and shares one electron with carbon, forming one C–Cl covalent bond.

Thus carbon forms four covalent bonds.

Structure:


       H

       |

H — C — Cl

       |

       H

Therefore, CH₃Cl contains three C–H bonds and one C–Cl covalent bond.

3. Write the differences between saturated and unsaturated hydrocarbons.


saturated hydrocarbons unsaturated hydrocarbons
They Contain Only Single bonds between carbon atoms They Contain One or more Double or triple bonds between carbon atoms
They are generally less reactive  they are generally more reactive 
Example: Ethane
(C2H6)
Example: Ethene ( C2H4)

Saturated hydrocarbons Contain only single bonds between carbon atoms.Called alkanes.

Unsaturated hydrocarbons Contain double or triple bonds between carbon atoms. Include alkenes and alkynes.

General formula of open-chain alkanes: CₙH₂ₙ₊₂

Alkenes: CₙH₂ₙ; Alkynes: CₙH₂ₙ₋₂

Generally undergo substitution reactions.

Generally undergo addition reactions.

Do not decolourise bromine water.

Decolourise bromine water.

Example: Ethane (C₂H₆)

Example: Ethene (C₂H₄)

4. Differentiate between alkanes, alkenes and alkynes.


Alkanes Alkenes Alkynes 
SaturatedUnsaturated  Unsaturated
Single bond (C-C) Double bond
(C=C) 
Triple bond 
(C=-C)
CnH2n+2 CnH2n CnH2n-2
Methane(CH4) Ethene(C2H4) Ethyne (C2H2)
Substitution Addition Addition


Examples of Structure:

Alkanes: CH3-CH3

Alkenes: CH2=CH2

Alkynes: CH=-CH

2 Marks Questions

1. Differentiate between saturated and unsaturated hydrocarbons with one example each.

saturated hydrocarbonsunsaturated hydrocarbons
They Contain Only Single bonds between carbon atomsThey Contain One or more Double or triple bonds between carbon atoms
They are generally less reactive they are generally more reactive 
Example: Ethane
(C2H6)
Example: Ethene ( C2H4)


2. Draw the structural isomers of butane. Name them.

Butane has the molecular formula C₄H₁₀ and has two structural isomers.

1. n-Butane:

CH₃ — CH₂ — CH₂ — CH₃

2. Isobutane (2-methylpropane):


       CH₃

        |

CH₃ — CH — CH₃


3. Why are carbon compounds poor conductors of electricity?

Carbon compounds are generally covalent compounds. They do not have free ions or free electrons that can carry electric current. Therefore, they are generally poor conductors of electricity.

4. Write two properties of ethane related to its use as a fuel.

Ethane is highly combustible and releases a large amount of heat on burning.

It burns in oxygen to produce carbon dioxide and water, releasing energy.

C₂H₆ + 7/2 O₂ → 2CO₂ + 3H₂O + heat

5. Explain why carbon forms a large number of compounds. Give any two reasons.

Carbon forms a large number of compounds mainly because of:

Catenation: Carbon atoms can bond with one another to form long chains, branched chains and rings.

Tetravalency: Carbon has valency 4 and can form four covalent bonds with carbon and other elements.


6. Why is a flame of unsaturated hydrocarbons smoky? How can we test for unsaturation?

Unsaturated hydrocarbons have a higher percentage of carbon. They often undergo incomplete combustion, producing tiny carbon particles (soot), which make the flame yellow and smoky.

Test for unsaturation: Add bromine water. An unsaturated hydrocarbon decolourises bromine water.

7. Write the chemical equation for esterification reaction. Name the ester formed from methanol and ethanoic acid.

Equation:

CH₃OH + CH₃COOH → CH₃COOCH₃ + H₂O

(conc. H₂SO₄, heat)

The ester formed is methyl ethanoate.

8. How is soap different from detergent? Give one point for each.

Soap: Forms scum with Ca²⁺ and Mg²⁺ ions in hard water and is therefore less effective.

Detergent: Does not form insoluble scum with Ca²⁺ and Mg²⁺ ions and works well in hard water.

9. What is meant by homologous series? Write two characteristics.

A homologous series is a group of organic compounds having the same functional group and the same general formula, where successive members differ by –CH₂–.

Characteristics:

Successive members differ by –CH₂– (14 u).

Members have similar chemical properties and show a gradual change in physical properties.


1 Marks Questions

1. The property of carbon to form chains, branched chains and rings is called:

Answer: B) Catenation

2. General formula of alkenes is:

Answer: CₙH₂ₙ

3. Which of the following is not an allotrope of carbon?

A) Diamond

B) Graphite

C) Fullerene

D) Methane

Answer: D) Methane

4. IUPAC name of CH₃CH₂OH is:

A) Methanol

B) Ethanol

C) Ethanal

D) Ethanoic acid

Answer: B) Ethanol

5. Which of the following belongs to the same homologous series?

Answer: B) C₂H₆ and C₃H₈

Both are alkanes and successive members differ by CH₂.


6. Functional group present in CH₃COOH is:

A) Alcohol

B) Aldehyde

C) Ketone

D) Carboxylic acid

Answer: D) Carboxylic acid

7. On adding sodium to ethanol, gas evolved is:

A) H₂

B) O₂

C) CO₂

D) CH₄

Answer: A) H₂ (Hydrogen)

2C₂H₅OH + 2Na → 2C₂H₅ONa + H₂↑

8. Draw the electron dot structure of methane.

Methane is CH₄. Carbon shares one electron with each of four hydrogen atoms.


       H

       :

   H : C : H

       :

       H

Each ":" represents a shared pair of electrons (covalent bond).

9. Why does carbon form covalent bonds only?

Carbon has four valence electrons. It is difficult for carbon to either lose four electrons or gain four electrons. Therefore, carbon completes its octet by sharing electrons, forming covalent bonds.

10. Name the catalyst used in hydrogenation of vegetable oils.

Answer: Nickel (Ni)


11. Why is conversion of ethanol to ethanoic acid considered an oxidation reaction?

Conversion of ethanol to ethanoic acid involves the addition of oxygen.

CH₃CH₂OH + 2[O] → CH₃COOH + H₂O

Therefore, it is considered an oxidation reaction.

12. Write the IUPAC name of CH₃–O–CH₃.

Answer: Methoxymethane

Common name: Dimethyl ether.


AP 9th Class Physics 3rd Lesson Force and Laws of Motion Questions and Answers

AP 9th Class Physics 3rd Lesson Force and Laws of Motion Questions and Answers (Exercise)

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Question 1.

An object experiences a net zero external unbalanced force. Is it possible for the object to be travelling with a non-zero velocity? If yes, state the conditions that must be placed on the magnitude and direction of the velocity. If not, provide a reason.

Answer:

Yes. Object can travel with non-zero velocity without experiencing net zero external unbalanced force in the space. However without unbalanced force the object can’t travel with non – zero velocity on the earth.

Question 2.
When a carpet is beaten with a stick, dust comes out of it. Explain.
Answer:

When a carpet is beaten with a stick it suddenly comes into motion.
But the dust in it continue to remain in rest due to inertia of rest.
Hence the dust comes out.


Question 3.
Why is it advised to tie any luggage kept on the roof of a bus with a rope?
Answer:


i) Backward – due to inertia of rest
ii) Forward – due to inertia of motion
iii) Sideways – due to inertia of direction
That’s why luggage should be tied.


Question 4.
A batsman hits a cricket ball which then rolls on a level ground. After covering a short distance, the ball comes to rest. The ball slows to a stop because
a) the batsman did not hit the ball hard enough.
b) velocity is proportional to the force exerted on the ball.
c) there is a force on the ball opposing the motion.
d) there is no unbalanced force on the ball, so the ball would want to come to rest.

Answer:


c) there is a force on the ball opposing the motion.

Question 5.
A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20. Find its acceleration. Find the force acting on it if its mass is 7 tonnes
(Hint : 1 tonne = 1000 kg)

Answer:

Truck: Initial velocity u=0; Displacement s=400m
Time t=20sec ; Mass m=7 tonnes =7000 kg [∵ 1 tonne =1000kg]



Question 6.
A stone of 1 kg is thrown with a velocity of 20 ms-1 across the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and the ice?
Answer:


Mass m =1 kg
Initial velocity u=20ms-1
Final velocity
v=0 (comes to rest); Displacement
s=50 m
From Kinematics,


Note : Friction force is always opposite to the motion.



Question 7.
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
a) the net accelerating force and
b) the acceleration of the train.

Answer:

Mass of enging = 8000 kg;
Mass of each wagon =2000 kg
Force generated by Engine =40000 N; Force of Friction =5000 N
a) Net Accelerating Force =40000-5000=35000 N
b) Acceleration of the train F = ma (Newton’s 2nd law)


Question 8.
An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of 1.7 ms-2?
Answer:

Automobile vehicle Visualisation :



Mass m =1500kg
Acceleration a =-1.7ms-2
F = ma × [By Newton’s 2nd law]
F=1500 × -1.7=-2550N
So, an opposite Force -2550 N should be applied to bring the vehicle to rest.
Question 9.
What is the momentum of an object of mass m, moving with a velocity v ?
a) (mv)2
b) mv2
c) 1/2 mv2
d) mv
Answer:
d) mv
Question 10.
Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet?
Answer:


Cabinet Visualisation:


To move the block with constant velocity across a floor the friction force exerted on the cabinet is -200 N.


Question 11.
According to the third law of motion when we push on an object, the object pushes back on us with an equal and opposite force. If the object is a massive truck parked along the roadside, it will probably not move. A student justifies this by answering that the two opposite and equal forces cancel each other. Comment on this logic and explain why the truck does not move.
Answer:

The boys reason is not correct. Heavier trucks have greater inertia, so it requires a greater unbalanced force to change its state of rest.


Question 12.
A hockey ball of mass 200 g travelling at 10 ms-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 ms-1. Calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Answer:




Question 13.
A bullet of mass 10 g travelling horizontally with a velocity of 150 ms-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on the bullet.
Answer:



Question 14.
An object of mass 1 kg travelling in a straight line with a velocity of 10 ms-1 collides with and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calcula inte the velocity of the combined object.
Answer:


Block – A
Mass m1= 1 kg
Initial velocity u1= 10 ms-1

Block – B
Mass m2 = 5 kg
Initial velocity u2= 0 ms-1



i) Block A is motion & Block B is at rest.
ii) Block A travelled in straight line & stuck with Block B.
iii) As they are moving together they will have a common velocity.
iv) Total momentum before collision = m1u1 + m2u2
= 1×10+5×0=10 kgms-1 or (N)

b) Momentum after Impact = 10 kg ms-1 (or) (N)
Reason : Momentum before collision is equal to momentum after collision.
c) Combined – velocity: m1u1 + m2u2 = m2v+ m2v
⇒ m1u1 + m2u2= v(m1+ m2)
⇒ 1 x 10 + 5 x 0 = v(1+ 5)

Question 15.
An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms-1 to 8 ms-1 in 6s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.
Answer:


Object:




Mass m = 100 kg Initial velocity u = 5 ms-1
Final velocity v = 8 ms-1,Time t, = 6 sec
Initial momentum P1 = mu = 100 x 5 = 500 kg ms-1 or (N)
Final momentum P2 = mv= 100 x 8 = 800 kg ms-1 (or) (N)




Question 16.
Akhtar, Kiran and Rahul were riding in a motorcar that was moving with a high velocity on an expresssway when an insect hit the windshield and got stuck on the windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because to the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect. And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions.
Answer:


Kiran Akhtar’s reasons are not correct.
Rahul’s suggestion is correct. Force exerted by windshield and insect are equal opposite according to Newton’s 3rd law.
But the mass of the insect is lesser than the mass windshield the insect experiences a greater force due to this it dies.


Question 17.
How much momentum will a dumb – bell of mass 10 kg transfer to the floor if it falls from a height of 80cm ? Take its downward acceleration to be 10 ms-2.
Answer:


Dumb-Bell :


SPECIAL TET FOR INSERVICE TEACHERS – AUGUST – 2026 Notification Schedule and INFORMATION BULLETIN

SPECIAL TET FOR INSERVICE TEACHERS – AUGUST – 2026 Notification Schedule and INFORMATION BULLETIN GOVERNMENT OF ANDHRA PRADESH

INFORMATION BULLETIN FORSPECIAL TET FOR INSERVICE TEACHERS - AUGUST-2026

Issuing of Notification and Publishing of Information bulletin for SPECIAL TET FOR INSERVICE TEACHERS – AUGUST – 2026 on 24.08.2026, candidates can applyfor SPECIAL TET FOR INSERVICE TEACHERS – AUGUST – 2026‘ONLINE’ only through APTET official website http://cse.ap.gov.in/ from 25.08.2026.


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1. Steps to be followed in submission of application online:

i. The candidates shall first download the ‘Information Bulletin’ from the APTET website http://cse.ap.gov.in/, go through it carefully and satisfy their eligibility for appearing for SPECIAL TET FOR INSERVICE TEACHERS – AUGUST – 2026.

ii. The candidate, after satisfying himself/herself about the eligibility criteria for APTET, shall first register by furnishing the basic details. Upon registration at APONLINE/e-Seva, the candidate shall be issued a ‘Journal Number’. Using this ‘Journal Number’, the candidate shall submit the application online from 25.08.2026 to 24.09.2026. After successful registration and submission of the application, the candidate shall pay a fee of Rs.1000/- for each subject through the Payment Gateway between 25.08.2026 to 24.09.2026. It is clarified that the issue of a ‘Journal Number’ does not imply completion of the application process; it merely acknowledges registration. Only those candidates who have successfully paid the prescribed fee and finally submitted the online application within the stipulated dates shall be considered as having successfully applied for

SPECIAL TET FOR INSERVICE TEACHERS–AUGUST – 2026.

iii. The candidates shall follow the procedure for submission of online application as given in the ‘Information Bulletin’ and instructions provided online while filling up the online application form. The Candidate should be ready with photograph of size 3.5X3.5cms before filling in online application.

a) Paste the photograph on a white paper and sign below (sign in Black Ink only). Look for the sample at point 12(ii), of the Information Bulletin.

Ensure that the signature is within the box. Scan the required size containing the photograph and signature. Please do not scan the complete page. The entire image consisting of photo along with signature is required to be scanned and stored in “jpeg” format on local machine.

Ensure that the size of the scanned image is not more than 50kb.If the size of the image is more than 50kb, then adjust the settings of the scanner such as dpi resolutions, number of colours during the process of scanning.

b) Applications with no photo / unclear photo / inadequate size photograph will be rejected. Hall – Ticket will not be issued to such candidates.

Hence, after pressing the ‘UPLOAD’ button check if the photo is of required size, clear and is of the same candidate of whom the details are to be filled in the application. If the photo is smaller in size, not clear or does not belong to the candidate press ‘BACK’ button below the photograph on the application form and restart with scanning of the photograph.

c) Complaints relating to mismatch of photograph and candidate details will not be accepted after submission of application at any cost.

2. Website: For latest updates, please check at APTET website http://cse.ap.gov.in/


Date and Timings:

APTET-In-service Teachers-2026 will be conducted as Online Computer Based Test as given below:

Dates of Exam Morning Session Timings Afternoon Session Timings
11.10.2026 onwards 09.30 AM to 12.00 AM

(2 Hours 30 Minutes)

2.30 PM to 5:00 PM

(2 Hours 30 Minutes)

3. Eligibility:

The In service (Regular and appointed on Minimum Time Scale) Teachers at the time of applying for SPECIAL TET FOR INSERVICE TEACHERS – AUGUST –2026 shall be having the minimum qualifications prescribed for Paper – I for Classes I to V (Regular Schools), Paper-II for classes VI to VIII (Regular Schools) as given below.

4. Qualifications:

i. All In-service (Regular and appointed on Minimum Time Scale) Teachers working in Government / Local Body / APREIS / Government Welfare Societies Residential / AP Model Schools / Pvt. Aided /Teachers working in other Government departments only are permitted to appear for Special APTET-August, 2026. 

ii. Pass in Special APTET-August, 2026 shall be considered as qualified only for fulfilment of the mandatory condition by all teachers either for continuing in their present post of working or promotion to the next higher post from the present post of working as per the orders of the Honourable Supreme Court of India in Civil Appeal No.1385/5025 and batch of other related Civil Appeals dt.01.09.2025.

iii. Pass in Special APTET-August, 2026 cannot be used for appearing in any direct recruitment in future. For appearing in any direct recruitment candidates need to appear for the regular APTET/ CTET.

iv. Secondary Grade Teachers and LFL Head Masters working in Government and Local Body Schools appointed with both D.El.Ed. and B.Ed. qualification are permitted to appear for Paper I.

v. School Assistants, TGTs, Language Pandits, Head Masters of High Schools are permitted to appear for Paper II.

vi. School Assistants who are working as PS HMs shall appear for paper-II in their concerned subject. 

5. Structure and Content of Special TET for In-Service Teachers – August 2026:

The structure and content of the Special TET for In-service Teachers is as follows:

a) All questions shall be Multiple Choice Questions (MCQs), each carrying one mark, with four alternatives out of which one answer shall be correct. There shall be no negative marking.

b) There shall be Two Papers for the Special TET for In-service Teachers.

Paper-I shall be for a person who intends to be a teacher for Classes I to V.

Paper-II shall be for a person who intends to be a teacher for Classes VI to VIII. 

c) SGT candidates who have both D.El.Ed and B.Ed qualifications are eligible for Paper-I and Paper-II

d) Paper-I : For Classes I to V (Regular Schools)

Number of Multiple-Choice Questions MCQs – 150

Duration of examination:2 hours and 30 minutes

Structure and Content (all compulsory)

S.No Subject No. of MCQs Marks
Part -1  Child Development and Pedagogy 30 MCQs 30 Marks
Part -2 Language- I (Optional -Telugu, Urdu, Hindi, Kannada, Tamil and  Odiya) 30 MCQs 30 Marks
Part -3 Language- II (Compulsory-English) 30 MCQs 30 Marks 
Part -4 Mathematics 30 MCQs 30 Marks
Part -5 Environmental Studies 30 MCQs 30 Marks

Total 150 MCQs 150 Marks

Note:-

I. The Test Items on Child Development and Pedagogy (CDP) shall focus on Nature and Scope of Educational Psychology, Growth and Development of child, Theories of Personality, Individual Differences, Learning,Assessment analysis, Mental Health, Guidance and Counselling etc.,relevant to the primary level. The syllabus designed for Child Development and Pedagogy is based on D.El.Ed curriculum of the State of Andhra Pradesh.

II. How to choose language–I of APTET Paper-I

The following languages are offered under First Language in the Schools under the State Syllabus viz., Telugu, Urdu, Hindi, Kannada, Tamil and Odiya., A candidate has to choose one of these six (6) languages under Language-I for APTET, those candidates shall have compulsorily studied that language either as medium of study or as First Language(or its equivalent)up to class X (or)as Second Language in Intermediate or concerned language as a subject at Graduation level and methodology in D.El.Ed is eligible for Paper-1A in concerned medium. 

III.English is compulsory language for all candidates as Language-II. 

IV.No candidate is allowed to opt English as optional Language as Language-I.

V. The syllabus for Language-I and Language-II prepared in order to test the Proficiency in the language, Elements of language,communication and comprehension abilities for 30 MCQs under Language- I and Language- II.

24 MCQs on content and 6 MCQs on Pedagogy of that Language.

VI.The syllabus for Mathematics & Environmental Studies is designed on the basis of topics of Classes III to VIII. The difficulty standard as well as linkages of content/topics could be up to Secondary Stage (up to Class X) for testing. The Test Items in Mathematics and Environmental Studies shall contain 30 Multiple Choice Questions (MCQs) each, both on Content and Pedagogy. In Mathematics, 24 MCQs on Content and 6 MCQs on Pedagogy. Similarly, in Environmental Studies 24 MCQs on Content and 6 MCQs on Pedagogy.

VII. The detailed syllabus for all subjects shall be designed by the SCERT(State Academic Authority) and the same shall be issued along with the Notification. Candidates are informed to follow Present (Academic Year 2025 - 2026) State Syllabus Textbooks of Class III to X. The candidates have to follow 2014 to 2025 editions of D.Ed / D.El.Ed Telugu Academy textbooks and 2019 editions of SCERT,D.El.Ed textbooks.

Note: Syllabus from Classes III to VIII and Standards Linkage Up to class X level. Questions shall be tested on critical thinking, creative thinking, and analytical thinking abilities of the candidates.

e) Paper-II: For Classes VI to VIII (Regular Schools)

Number of Multiple-Choice Questions (MCQs)– 150

Duration of examination: 2 hours and 30 minutes

Structure and Content (all compulsory)

S.NoSubjectNo. of MCQsMarks
Part -1 Child Development and Pedagogy30 MCQs30 Marks
Part -2Language- I (Optional -Telugu, Urdu, Hindi, Kannada, Tamil and  Odiya)30 MCQs30 Marks
Part -3Language- II (Compulsory-English)30 MCQs30 Marks 
Part -4

Mathematics & Science:

i)Mathematics

(Content 16, Pedagogy 4)

ii)Physical Science 

(Content 16, Pedagogy 4)

iii)Biological Science 

(Content 16, Pedagogy 4) 

---------------------------------------

Social Studies

(Content 48, Pedagogy 12)

60 MCQs60 Marks

Language

(Content 48, Pedagogy 12)

60 MCQs60 Marks

Total150 MCQs150 Marks

Note:-

i) The Test Items on Child Development and Pedagogy (CDP) focus on Nature and scope of educational psychology, Growth and Development of child, Theories of Personality, Individual Differences, Learning,Assessment and its analysis, Mental Health, Guidance and Counselling etc., relevant to the Secondary level. The syllabus designed for Child Development and Pedagogy is based on B.Ed curriculum of the State of Andhra Pradesh.

ii) How to choose Language – I of APTET Paper- II: 

The following languages are offered under First Language in Secondary Schools under the State Syllabus viz., Telugu, Urdu, Hindi, Kannada, Tamil, Odiya and Sanskrit. Candidate has to choose one of these seven (7) languages under Language-I (Optional) of APTET Paper-II. Those candidates shall have compulsorily studied that Language either as medium of study or First Language (or its equivalent) up to class X (or) second language in Intermediate or concerned language as a subject at Graduation level are eligible for Paper-II in concerned medium.

iii) Note: All School assistant Language teachers except English Language teachers shall opt their concerned subject as first language only.

iv) English is compulsory language for all candidates as Language-II. 

v) No candidate is allowed to opt English as optional Language as Language -I.

vi) The syllabus for Language I & II for Paper-II shall be based on proficiency in the Language, Elements of Language, Communication and Comprehension abilities. Standard of test items are from VI to Senior Secondary Level (Intermediate) –XII Class level. 

vii) 30 MCQs for Language -I and 30 MCQs for Language- II will be given on content only.

viii) The syllabus for APTET of concerned Paper-II are based on topics of Classes VI to X. The difficulty level and standard of questions as well as their linkages could be up to Senior Secondary(Intermediate) Level (XII class). Candidates shall follow Present (2025-26) State Syllabus Textbooks of Class VI to X. The candidates shall follow 2014 to 2025 editions of D.Ed / D.El.Ed / B.Ed Telugu Academy Text books and 2019 editions of D.El.Ed - SCERT Textbooks.

Note: Syllabus from Classes VI to X and standards linkage up to Intermediate level. Questions shall be tested Conceptual understanding, critical thinking, creative thinking, and analytical thinking abilities of the candidates.

g) Syllabus: Detailed syllabus for Paper-I and Paper-II for each subject shall be notified on official website http://cse.ap.gov.in.


The syllabus mentioned in the official website is suggestive but not exhaustive.

6. Medium of Question Paper:

The Question Paper shall be bilingual (i.e.,) English followed by the Language- I chosen by the candidates. 

Note:

1. For the candidates choosing Sanskrit in Paper-II, Child Development and Pedagogy (CDP) is in Telugu followed by Sanskrit. Language-II in English (compulsory). Language -I and the remaining part of the question paper shall be in Sanskrit.

2. There is no option for Hindi/Sanskrit medium for Non language Subjects.

7. Pass Criteria of SPECIAL TET FOR INSERVICE TEACHERS – AUGUST  2026:

Results shall be declared as per the schedule notified. The criteria for considering pass in APTET are as follows: (Total Marks-150)

Community Pass Percentage  Pass Marks
i) OC/EWS 60% and above 90 Marks and above
ii) BC  50% and above 75 Marks and above
iii) SC/ ST/ PwBD& Ex-

Servicemen
40% and above 60 Marks and above

Note:

i) Differently abled (Visually, Orthopedically, Hearing Impaired and Autism) candidates with at least 40% of disability shall be considered as disabled except Hearing Impairment. Hearing Impairment means

 (a) Deaf means person having 70 DB hearing loss in speech frequencies in both ears

 (b) Hard of Hearing means person having 60 DB to 70 DB hearing loss in speech frequencies in both ears (GO.MS.No:36, Dept for Woman, Children,Differently Abled & Senior citizens (Prog.ii) Dt: 23-08-2023.). 

ii) The Certificate shall contain the Name and Address of the Candidate,Registration No., Year/ Month of Award of Certificate, Marks obtained in each Paper, Class level of its validity (Class I to V (or) Class VI to VIII) and in case of Classes VIto VIII the Subject Area (Languages/ Mathematics, Physical Science, Biological Science/ Social Studies) etc., The Certificate may be electronically generated with adequate security features to avoid any kind of malpractice.

iii) The Joint Director, TET and Member Convener, Andhra Pradesh shall issue Memo/ Pass Certificate in Digital Format to the candidates. Certificates shall be also be made available in Digi Locker from publishing of APTET results.

8. Certificate Validity Period/ Marks Memo:

The Marks Memo/Certificate of Special TET for In Service Teachers – August 2026 Examination shall be made available on APTET website only. There is no restriction on the number of attempts and a person can take attend any number of times for acquiring APTET Certificate. The APTET certificate shall be valid for life time in accordance with NCTE guidelines dated: 09.06.2021 as amended by the Government in G.O.Ms.No.69, Dated: 25.10.2021.

Note: The Special TET for In Service Teachers – August 2026 Examination certificate shall remain valid for life time unless otherwise modified by future NCTE guidelines.

9. Procedure for applying ONLINE:

The candidates shall at first download the ‘Information Bulletin’ (free of cost) from the APTET website http://cse.ap.gov.in, go through it carefully and satisfy their eligibility for appearing for Special TET for In Service Teachers – August 2026 Examination.

i) The candidate, after satisfying himself/herself about the eligibility criteria for APTET, shall first register by furnishing the basic details. Upon registration at APONLINE/e-Seva, the candidate shall be issued a ‘Journal Number’. Using this ‘Journal Number’, the candidate shall submit the application online from 25.08.2026 to 24.09.2026. After successful registration and submission of the application, the candidate shall pay a fee of Rs.1000/- for each subject through the Payment Gateway between 25.08.2026 to 24.09.2026. It is clarified that the issue of a ‘Journal Number’ does not imply completion of the application process; it merely acknowledges registration. Only those candidates who have successfully paid the prescribed fee and finally submitted the online application within the stipulated dates shall be considered as having successfully applied for APTET.

ii) The candidates shall follow the procedure of submission of online application as given in the ‘Information Bulletin’ and also as per the instructions provided online while filling up the online application form.

The Candidate should be ready with photograph of size 3.5X3.5cms

before filling in on-line application.’

iii) Paste the photograph on a white paper and sign below (sign in Black Ink only). Observe the sample given above. Ensure that the signature is within the box. Scan the required size containing the photograph and signature. Please do not scan the complete page. The entire image consisting of photo along with signature is required to be scanned and stored in .jpeg format on local machine. Ensure that the size of the scanned image is not more than 50kb. If the size of the image is more than 50kb, then adjust the settings of the scanner such as dpi resolutions, number of colours during the process of scanning.

a) Applications with no photo/ unclear photo/ inadequate size photograph will be rejected. Hall-Ticket will not be issued to such candidates. Hence, after pressing the 'UPLOAD' button check if the photo is of required size, clear and is of the same candidate of whom the details are to be filled in the application. If the photo is smaller in size, not clear or does not belong to the candidate press 'BACK' button below the photograph on the application form and restart with scanning of the photograph.

b) Complaints relating to mismatch of photograph and candidate details will not be accepted after submission of application at any cost.

iv) Initial steps to be followed before filling Online Application Form.


a) Go to http://cse.ap.gov.in

b) Click on “Apply Online” / “Application Link”: On the homepage you’ll find the link when the application window is open. 

c) Click on the new register dialogue box.

d) Provide basic details (i.e., Name,father /mother’s name, DOB, Aadhaar number, email ID, mobile number, gender, category, address etc.,).

e) At the field ‘Attach your latest photograph' Click on Browse button and attach your photograph and your signature stored on the local machine.

f) Press Upload and Tick the declaration and enter the verification code.

g) Confirm the next dialogue box and create login credentials (user-ID / password).

h) Enter your Journal Number and login to application form and fill the educational qualifications. 

i) After filling all the details press PREVIEW button. This will display the details submitted by you.

j) Choose the paper(s) you’re applying for.

k) Fill the application form as per the instructions given in the User Guide and Information Bulletin and those offered while filling the Online Application Form.

l) If you find all the details correct press SUBMIT otherwise press EDIT and resubmit the information.

m) Pay the required application fee (e.g., for each paper) and complete the application.

n) On completion of submission, the candidates shall take a printout of the application and store it for future use. Candidates should not post the printout of the application to APTET office.

v) For domain related clarifications contact APTET office at Director/Commissioner of School Education, Mangalagiri, Amaravati,Andhra Pradesh.

vi) In any case applications will not be received in any kind of manual form.

10. Fee Particulars:

The fee towards submission of application online and for the conduct of Computer Based TET examination is Rs.1000.00/-. for each Paper. If the candidate desires to appear for all papers he/she has to pay an amount of Rs.1000.00/ for each paper separately. Candidates shall pay the fee through payment Gateway between 25.08.2026 to 24.09.2026 and submit online application at the APTET website http://cse.ap.gov.in between 25.08.2026 to 24.09.2026.


AP SPECIAL TET AUGUST 2026 SCHEDULE


S.No SUBJECT DATES
1 Date of Notification and Publishing of Information Bulletin 24-08-2026
2

Payment of Fees through Payment Gateway

25.08.2026 to 24.09.2026
3

Online submission of application through http://cse.ap.gov.in

25.08.2026 to 24.09.2026
4 Online Mock Test availability 25-09-2026
5 Download of Hall Tickets 05-10-2026 Onwards
6 Schedule of examination From 11-10-2026 to 21-10-2026 Both sessions in all days Session-1: 9.30 AM to 12.00 Noon Session-II: 2.30 PM to 5.00 PM
7 Release of Initial Key 24-10-2026
8 Receiving of objection on Initial Key From 25-10-2026 Το 01-11-2026
9 Release of final key 10-11-2026
10 Final results declaration 15-11-2026

11. PROCESS FOR CONDUCT OF COMPUTER BASED TEST (CBT):

In order to bring in utmost transparency and accuracy in the conduct of examinations, it is decided to conduct APTET examination in Computer Based Test (CBT) mode. The Computer Based Test involves registration of candidates and application processing, identification of Test centres, Test centres management, generation of hall tickets, awareness to the Candidate about CBT by means of conduct of mock tests. The examination management includes digitalization and secured transfer of the question paper to the Test centres, conduct of test, processing of scores and generation of score cards as per the Government Orders.

(a) PROCESS INVOLVED IN COMPUTER BASED TEST (CBT):

i. The agency identified by the Commissioner / Director of School Education shall design, develop and host the web based secured application form for Department and accept applications.

ii. Integration with Payment Gateway for online fee payment. 

iii. Test Centres should be identified by the agency and must meet rigorous compliance requirements. The Test centres should also be completely secured & sanitized to prevent any malpractices.

iv. Standard Test centres used for prestigious nationwide competitive exams like IIT JEE Main, IIT GATE, IIM CAT, RRB, IBPS, etc., should be utilized for APTET Examination. 

v. The Computer Based Test shall be conducted in all the districts. A candidate shall appear for the Written Test (Computer Based Test) in the district in which he/she seeks (or) in adjacent districts within the State (or) adjacent district of neighbouring States as far as possible. 

vi. The Commissioner / Director of School Education shall issue detailed instructions to ensure proper conduct of APTET. 

vii. The candidates who are found copying or resorting to other means of malpractice, shall be expelled from the examination hall apart from being debarred from appearing for the examinations conducted by the Department for three consecutive examinations, besides taking action as per the Andhra Pradesh Public Examination (Prevention of Malpractices and Unfair means) Act, 1997 (No. 25 of 1997).

viii. Disciplinary action shall be initiated against such staff who are found negligent in the discharge of their duties and an entry shall be made accordingly in the Service Register of the concerned staff, besides taking action as per the Andhra Pradesh Public Examination (Prevention of Malpractices and unfair means) Act, 1997 (No. 25 of1997).

ix. The Computer Based Test (CBT) shall be in English followed by the medium opted by the candidate. 

x. One Gazetted Officer of School Education Department (MEO/Gazetted Head Master/Deputy DEO) may be drafted as Departmental Officer for the Test centres to assist the Technical persons.

(b) CONSTITUTION OF EXAMINATION CENTRES FOR SPECIAL TET FOR INSERVICE TEACHERS – AUGUST 2026:

i. The identification of Examination centers and confirmation of Examination centers is the sole responsibility of the Agency which is entrusted to conduct A.P. Teacher Eligibility Test (APTET) as Computer Based Test. 

ii. Each Centre should be equipped with good accommodation, furniture and computer infrastructure. Each Centre shall have a capacity to accommodate 300-500 candidates in a single session. 

iii. The Centers in the District shall be identified preferably in District Head Quarters, Municipalities, Revenue division and Mandals. 

iv. Where required, based on number of applicants, particular category of post and subject, centers may be identified in the adjacent district of neighbouring States. 

v. Institutions having spacious and sufficient number of rooms and computer infrastructure are to be constituted as Examination centers. Institutions proposed to be constituted as Examination centers shall be inspected by District Educational Officer of the concerned District personally. The number of rooms available in each center and number of candidates to be accommodated in each room, shall be ascertained before allotting the candidates to any of the Examination Centers.

12. Normalization:

The following standard Normalization procedure/Technique will be adopted for APTET.

M^ij= Normalized marks of jth Candidate in the ith Shift

Mt

g

= is the average marks of the top 0.1% of the candidates considering all shifts (number of candidates will be rounded – up)

Mq

g

= is the sum of mean and standard deviation marks of the candidates in the examination considering all shifts

Mti = is the average marks of the top 0.1% of the candidates in the ith shift

(number of candidates will be rounded up)

Miq = is the sum of the mean marks and standard deviation of the ith shift

Mij = is the actual marks obtained by the jth Candidate in the ith Shift

Mq

gm

= is the sum of mean marks of Candidates in the Shift having maximum mean and standard deviation of marks of candidates in the examination considering all.

Note: Calculation of marks will be up to 5 decimal places


13. Hall Tickets:

Candidates can download their Hall Tickets from the official website at http://cse.ap.gov.in from 05.10.2026 onwards. In case of any candidate could not download the Hall ticket he/ she should contact the Office of the Director/Commissioner of School Education, Mangalagiri, Amaravati, Andhra Pradesh between 10.00 AM to 5.30 PM on all working hours in person by giving details of the Journal Number of the fee paid, reference number of the application submitted, a copy of the printout of the Application form and one photograph (same photograph as pasted on the application form).Request for issue of duplicate Hall Ticket will not be entertained after the examination in any case.

14. OBJECTIONS ON KEY:

i. The Subject expert committee constituted by SCERT (The State Academic Authority) is the final authority to redress the objections on the initial key. 

ii. No objections shall be entertained on the final key. 

15. Help Desk

In case of any clarifications before, during or after submission of online application the candidates may contact the Help Desk from 10.00 A.M. to 5.30 P.M. on all working days from 24.08.2026 Onwards.(Help Desk Contact numbers:

(8121947387, 7995649286, 6281704160)

16. Legal Jurisdiction:

All legal disputes with regard to the conduct of TET shall be subject to the Jurisdiction of the Courts located in the State of Andhra Pradesh only.


ONLINE APPLICATION SUBMISSION LINK

Download AP TET INSERVICE TEACHERS Notification 

TET Information Bulletin Download here

AP TET SCHEDULE DOWNLOAD HERE

AP TET INSERVICE TEACHERS PRESS NOTE DOWNLOAD HERE 

Special TET GOVT MEMO DOWNLOAD HERE 

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సాధనం–1: విద్యార్థుల భాగస్వామ్యం, ప్రతిస్పందనలు

✅ 5 మార్కులు – పూర్తి మార్కులు

🟢 విద్యార్థి తరగతిలో చురుకైన భాగస్వామ్యం చూపించి, ప్రశ్నలకు సరైన సమాధానాలు ఇచ్చాడు/ఇచ్చింది. విషయాన్ని పూర్తిగా అర్థం చేసుకొని, తన ప్రతిస్పందనలో స్పష్టత మరియు ఆత్మవిశ్వాసాన్ని ప్రదర్శించాడు/ప్రదర్శించింది. క్రమశిక్షణతో, శ్రద్ధగా పాల్గొన్నందుకు పూర్తి 5 మార్కులు ఇవ్వబడినవి.

✅ 4 మార్కులు

🟢 విద్యార్థి ప్రశ్నలకు సమాధానాలు ఇచ్చినప్పటికీ, కొన్ని అంశాల్లో స్పష్టత లోపించింది. విషయాన్ని అర్థం చేసుకున్నప్పటికీ, పూర్తి సమాధానం ఇవ్వలేకపోయాడు/లేకపోయింది. కాబట్టి 4 మార్కులు ఇవ్వబడినవి.

✅ 3 మార్కులు

🟢 విద్యార్థి ప్రశ్నలకు కొంతవరకు సమాధానం ఇచ్చాడు/ఇచ్చింది. ప్రధాన అంశాల్లో కొన్ని మిస్‌ అయినప్పటికీ, నేర్చుకోవాలనే ప్రయత్నం స్పష్టంగా కనిపించింది. మరింత శ్రద్ధ వహిస్తే మంచి ఫలితాలు సాధించగలడు/గలదు. కాబట్టి 3 మార్కులు ఇవ్వబడినవి.

✅ 2 మార్కులు

🟢 విద్యార్థి ప్రశ్నకు కొంతమేర మాత్రమే సమాధానం ఇచ్చాడు/ఇచ్చింది. విషయాన్ని పూర్తిగా అర్థం చేసుకోలేకపోయినా, సమాధానం ఇవ్వడానికి ప్రయత్నించాడు/ప్రయత్నించింది. మరింత శ్రద్ధతో అభ్యసిస్తే మెరుగైన ఫలితాలు సాధించగలడు/గలదు. కాబట్టి 2 మార్కులు ఇవ్వబడినవి.

✅ 1 మార్కు

🟢 విద్యార్థి ప్రశ్నకు సరైన సమాధానం ఇవ్వలేకపోయినా, సమాధానం ఇవ్వడానికి ప్రయత్నించాడు/ప్రయత్నించింది. మరింత అభ్యాసం, శ్రద్ధ అవసరం ఉంది. క్రమంగా మెరుగుపడతాడని/మెరుగుపడుతుందని ఆశిస్తున్నాను. కాబట్టి 1 మార్కు ఇవ్వబడినది.



FA Tool–2 : Written Work

To be filled by the Teacher | ఉపాధ్యాయుడు/ఉపాధ్యాయురాలు నమోదు చేయాలి

0 – Not Done | చేయలేదు

🔹 English: No written work was submitted.

🔹 తెలుగు: ఎటువంటి రాతపని సమర్పించలేదు.

1 – Need Improvement | మెరుగుదల అవసరం

🔹 English: Very little work was done; there are errors in presentation and participation is low.

🔹 తెలుగు: చాలా తక్కువ రాతపని చేశారు; ప్రదర్శనలో/రాతలో తప్పులు ఉన్నాయి; పాల్గొనడం తక్కువగా ఉంది.

2 – Satisfactory | సంతృప్తికరం

🔹 English: Less than half of the work was completed; literacy/writing skills show average interest.

🔹 తెలుగు: సగానికి తక్కువ రాతపని పూర్తయింది; చదవడం–రాయడం పట్ల సగటు స్థాయి ఆసక్తి కనబరుస్తున్నారు.

3 – Good | బాగుంది

🔹 English: The work is complete but needs improvement in writing and presentation.

🔹 తెలుగు: రాతపని పూర్తయింది; అయితే రాత మరియు ప్రదర్శనలో మరింత మెరుగుదల అవసరం.

4 – Very Good | చాలా బాగుంది

🔹 English: Most of the work is completed; a little editing is needed; good participation and sharing.

🔹 తెలుగు: ఎక్కువ భాగం రాతపని పూర్తయింది; కొద్దిపాటి సవరణ అవసరం; మంచి భాగస్వామ్యం మరియు పంచుకునే నైపుణ్యం ఉంది.

5 – Excellent | అత్యుత్తమం ⭐

🔹 English: The syllabus was completed on time; all written work is neat and correct; active participation in all activities.

🔹 తెలుగు: నిర్ణీత సమయంలో సిలబస్ పూర్తిచేశారు; రాతపని అంతా శుభ్రంగా, సక్రమంగా ఉంది; అన్ని కార్యకలాపాల్లో చురుకుగా పాల్గొన్నారు.



AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 TELUGU ALL CLASSES (1ST TO 10TH)


2nd Class Telugu Tool 1 Download 

3rd ,4th,5th Class Telugu Tool 1 Download 

6th Class Telugu Tool 1 Download 

6th to 10th Class Telugu Tool 1 Download 

6th to 10th Class Telugu Tool 1 Download 

10th Class Telugu Tool 1 Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 Hindi ALL CLASSES (6TH TO 10TH)


6th Class Tool 1 & Tool 2 pdf Download 

7th Class Tool 1 & Tool 2 pdf Download 

8th Class Tool 1 & Tool 2 pdf Download 

9th Class Tool 1 & Tool 2 pdf Download 

10th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 ENGLISH ALL CLASSES (1ST TO 10TH)


1st Class Tool 1 & Tool 2 pdf Download 

2nd Class Tool 1 & Tool 2 pdf Download 

3rd Class Tool 1 & Tool 2 pdf Download 

5th Class Tool 1 & Tool 2 pdf Download 

4th Class Tool 1 & Tool 2 pdf Download 

6th to 10th Class Tool 1 & Tool 2 pdf Download 

6th to 10th Class Tool 1 & Tool 2 pdf Download 

6th to 10th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 MATHS ALL CLASSES (1ST TO 10TH)


3rd to 5th Class Tool 1 & Tool 2 pdf Download

2nd Class Tool 1 & Tool 2 pdf Download 

6th Class Tool 1 & Tool 2 pdf Download 

6th Class Tool 1 & Tool 2 pdf Download 

7th Class Tool 1 & Tool 2 pdf Download 

7th Class Tool 1 & Tool 2 pdf Download 

8th Class Tool 1 & Tool 2 pdf Download 

8th Class Tool 1 & Tool 2 pdf Download

9th Class Tool 1 & Tool 2 pdf Download 

9th Class Tool 1 & Tool 2 pdf Download

10th Class Tool 1 & Tool 2 pdf Download 

10th Class Tool 1 and Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 EVS ALL CLASSES (3RD TO 5TH)


3rd Class Tool 1 & Tool 2 pdf Download 

4th Class Tool 1 & Tool 2 pdf Download 

5th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 GENERAL SCIENCE ALL CLASSES (6TH & 7TH)

6th Class Tool 1 & Tool 2 pdf Download 

7th Class Tool 1 & Tool 2 pdf Download 

6th Class Tool 1 & Tool 2 pdf Download 

7th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 PHYSICS ALL CLASSES (8TH TO 10TH)


8th to 10th Class Tool 1 & Tool 3 pdf Download 

9th Class Tool 1 & Tool 2 pdf Download 

10th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 BIOLOGY ALL CLASSES (8TH TO 10TH)


8th Class Tool 1 & Tool 2 pdf Download 

9th Class Tool 1 & Tool 2 pdf Download 

10th Class Tool 1 & Tool 2 pdf Download 

AP FORMATIVE ASSESSMENT – TOOL–1, TOOL-2 SOCIAL ALL CLASSES (6TH TO 10TH)


6th to 10th Class Tool 1 & Tool 2 pdf Download 

6th to 10th Class Tool 1 & Tool 2 pdf Download 

9th & 10th Class Tool 1 & Tool 2 pdf Download  

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